实验题目描述：

编程实现兔⼦问题，历史上有⼀个有名的关于兔⼦的问题：假设有⼀对兔⼦，⻓两个⽉它们就算⻓⼤成年了。然后以后每个⽉都会⽣出1对兔⼦，⽣下来的兔⼦也都是⻓两个⽉就算成年，然后每个⽉也都会⽣出1对兔⼦了。这⾥假设兔⼦不会死，每次都是只⽣1对兔⼦，实现计算第20个（第 15）⽉的兔⼦对数

加入条件，每对兔⼦⽣完2次（N次）兔⼦后会死亡，实现计算第20个（第15）⽉的兔⼦对数

隔⼏个⽉后可以繁殖设置为参数K, 繁殖⼏代后死亡设置成参数P,计算第N个⽉的兔⼦对数

题目分析：

看似题目是三个逐步递进的过程，其实还是比较简单的，只需要建立一个简单的结构体或者类，，然后根据相应的标志位设置是否死亡，是否长大，是否新生，是否可繁殖这四步，主要的其实是两个动作，一个出生，一个死亡，就是结构体数组的删除和新建罢了，后面放出源码，未加入繁殖两代之间的间隔，可自行加入，大家仅供参考，不可原版照抄！

题目实现源码

#include
   
    #include
    
     #include
     
      #include
      
       using namespace std;class rabbit {private:	bool Is_Adult;	bool Is_Death;	int Grown_Time;	int Breed_Time;	int DEATH_TIME;	int MATURE_TIME;public:	rabbit(int Death_Time, int Mature_Time) {		DEATH_TIME = Death_Time;		MATURE_TIME = Mature_Time;		Is_Adult = false;		Is_Death = false;		Grown_Time = 0;		Breed_Time = 0;	}	bool Get_Is_Adult() {		return Is_Adult;	}	bool Get_Is_Death() {		return Is_Death;	}	int Get_Grown_Time() {		return Grown_Time;	}	int Get_Breed_Time() {		return Breed_Time;	}	void Add_Grown_Time() {		Grown_Time++;		if (Grown_Time >= MATURE_TIME)			Is_Adult = true;	}	void Add_Breed_Time() {		Breed_Time++;		if (Breed_Time >= DEATH_TIME)			Is_Death = true;	}};int Compute_Num(int Month_Num, vector
       
        Rabbits, int Death_Time, int Mature_Time) {	for (int i = 0; i < Month_Num; i++)	{		int Rabbits_Size_Now = Rabbits.size();		int Dead_Rabbits = 0;		int Born_Rabbits = 0;		for (int j = 0; j < Rabbits_Size_Now;)		{			if (Rabbits[j].Get_Is_Death())			{				Rabbits.erase(Rabbits.begin() + j);				Rabbits_Size_Now--;				Dead_Rabbits++;				continue;			}			if (Rabbits[j].Get_Is_Adult()) {				rabbit *r = new rabbit(Death_Time, Mature_Time);				Rabbits.push_back(*r);				Rabbits[j].Add_Breed_Time();				Born_Rabbits++;				Rabbits_Size_Now++;				if (Rabbits[j].Get_Is_Death())				{					Rabbits.erase(Rabbits.begin() + j);					Rabbits_Size_Now--;					Dead_Rabbits++;					continue;				}			}			else				Rabbits[j].Add_Grown_Time();			j++;		}		printf("The %2d month has %2d rabbits!\n",i+1,Rabbits.size());		if (Dead_Rabbits)			printf("The %2d month has %2d rabbits dead!\n", i+1,Dead_Rabbits);		if (Born_Rabbits)			printf("The %2d month has %2d rabbits born!\n", i+1, Born_Rabbits);		//cout << "The " << i + 1 << " month has " << Rabbits.size() << " rabbits!" << endl;	}	return Rabbits.size();}int main() {	int Death_Time, Mature_Time, Month_Num;	char s[200] = "Example: Death_Time = 100000000, Mature_Time = 2, Month_Num = 12";	cout << "/";	for (int i = 0; i < strlen(s); i++)		cout << "*";	cout << "/"<
        
         > Death_Time; while (cin.fail()) { cout << "Wrong, you have inputed a wrong type data!" << endl; cin.clear();//清除错误标记，重新打开输入流，但是输入流中依旧保留着之前的不匹配的类型 /*cin.sync();*///清楚cin缓存区的数据。 while (cin.get() != '\n') { continue; } cout << "please input Death_Time again" << endl; cin >> Death_Time; } cout << "Please input Mature_Time: "; cin >> Mature_Time; while (cin.fail()) { cout << "Wrong, you have inputed a wrong type data!" << endl; cin.clear();//清除错误标记，重新打开输入流，但是输入流中依旧保留着之前的不匹配的类型 /*cin.sync();*///清楚cin缓存区的数据。 while (cin.get() != '\n') { continue; } cout << "please input Mature_Time again" << endl; cin >> Mature_Time; } cout << "Please input Month_Num to Compute: "; cin >> Month_Num; while (cin.fail()) { cout << "Wrong, you have inputed a wrong type data!" << endl; cin.clear();//清除错误标记，重新打开输入流，但是输入流中依旧保留着之前的不匹配的类型 /*cin.sync();*///清楚cin缓存区的数据。 while (cin.get() != '\n') { continue; } cout << "please input Month_Num again" << endl; cin >> Month_Num; } vector
         
          Test; rabbit* a = new rabbit(Death_Time, Mature_Time); Test.push_back(*a); int rabbit_sum_num = Compute_Num(Month_Num, Test, Death_Time, Mature_Time); }}

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